8[2-(3+4x)]-4x=10+2(1-18x)

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Solution for 8[2-(3+4x)]-4x=10+2(1-18x) equation: 


Simplifying
8[2 + -1(3 + 4x)] + -4x = 10 + 2(1 + -18x)
8[2 + (3 * -1 + 4x * -1)] + -4x = 10 + 2(1 + -18x)
8[2 + (-3 + -4x)] + -4x = 10 + 2(1 + -18x)

Combine like terms: 2 + -3 = -1
8[-1 + -4x] + -4x = 10 + 2(1 + -18x)
[-1 * 8 + -4x * 8] + -4x = 10 + 2(1 + -18x)
[-8 + -32x] + -4x = 10 + 2(1 + -18x)

Combine like terms: -32x + -4x = -36x
-8 + -36x = 10 + 2(1 + -18x)
-8 + -36x = 10 + (1 * 2 + -18x * 2)
-8 + -36x = 10 + (2 + -36x)

Combine like terms: 10 + 2 = 12
-8 + -36x = 12 + -36x

Add '36x' to each side of the equation.
-8 + -36x + 36x = 12 + -36x + 36x

Combine like terms: -36x + 36x = 0
-8 + 0 = 12 + -36x + 36x
-8 = 12 + -36x + 36x

Combine like terms: -36x + 36x = 0
-8 = 12 + 0
-8 = 12

Solving
-8 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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